Re: 3 point hitch on M

Posted by HavinFunin MO on January 08, 2003 at 18:06:08 from (67.28.92.112):

In Reply to: 3 point hitch on M posted by HACK on January 08, 2003 at 15:34:04:

Let me see if I can give you a couple formulas to get you headed in the right direction. To find out each cylinders capacity you need to know the area.
Formula for area of a circle is pi (3.14156) mulitplied by the radius squared
thereby, a 2.5 inch would be 3.14156 x (1.25 x 1.25)[radius squared] = 4.91 square inches
& thereby, a 3.0 in would be 3.14156 x (1.5 x 1.5) [radius squared] = 7.07 square inches

taking the above formulas and mutliplying the total area for each cylinder by the working psi of your hydraulic system will give the weight the cylinder can move.
(remember that a retracting cylinder has less ability to do work as the rod takes up some of the area. ex. a 2.5 inch cylinder with 4.91 square inches of area and a 1 inch rod that takes up .79 square inches leaves 4.12 square inches when retracting.)
The lift arms will reduce the cylinders ability to lift. This is diffucult to explain without knowing how your system is designed. In the simplest of designs were the cylinders attach directly to the lift arms, the calculation would go something like this. A 20 inch lift arm (measured from pivot to attachment point) that has a cylinder attached at 10 inches (measured from pivot point to attachment point again) would be 10 divided by 20 = .5 or 50% reduction in lifting capacity.

Follow Ups:

• Re: Re: 3 point hitch on M Haas 06:09:12 01/09/03 (0)
• Re: Re: 3 point hitch on M Jon Blanc 03:25:46 01/09/03 (0)

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