hyd cylinder calculations

Force of a cylinder is area of the piston X the hydraulic pressure exerted.

3.14 x radius squared x hydraulic pressure 2200 psi so for a 2 in cylinder.

For example

3.14 x 1 x 1 x 2200 = 6908 lbs of force per cylinder.

The angle of the cylinder will also affect the amount the cylinder will lift. A straight pus is best.

The push force is pressure x pi r squared

So, your 2 inch cylinder has an r of 1 inch (half the diameter). I'm going to guess your pressure at 1000 psi (cuz it's easier for me!)

1000 * 3.14159 * 1*1 = 3141.6 pounds of force.

The pull force is the same, but you have to also do it for the rod and subtract that number from the 3141.6. The rod takes up space on the surface that pushes and that's why it is subtracted.

You have to do triangles to determine effective force by calculating the vertical component of the force provided by the cylinder. If you don't know what that means, then draw out a measured picture of the mounted cylinder in the retracted position and the extended position and post that here. The math will get done for you.

jb