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Ford 9N, 2N & 8N Discussion Forum
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12v coil ? on 6 volt ?

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Ken(Ark)

02-17-2007 20:45:54




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If a 6 volt coil uses 3.5 volts to run , then would a 12v coil be too weak on a 6 volt system . I dont have a clue here , and I am assuming the answer is no or every body would be doing this .

Didn't I see a conversion kit that has a special cap that lets you use a can coil on your front mount distributer ? Do the can coils run on 6 volts on the side mount distributers or do you drop the volts on those also ?

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uh . . . Dell (WA)

02-18-2007 08:26:31




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 Re: 12v coil ? on 6 volt ? in reply to Ken(Ark), 02-17-2007 20:45:54  
Ken..... ..once again for the electrically challenged. You CAN NOT run a 12v coil on 6v. WHY? because every electrical component has to be designed specifically for its own operating voltage. Resistors REDUCE VOLTS and can NOT INCREASE volts. EVER!!! Its the LAW!!!

Therefore, despite wishful thinking on your part, any 12-volt ignition coil (even with gazillion sparkies volts) trying to being run on 6-volts will have WEAKzillion sparkie volts. Guess what? engines don't run on WEAK sparkies.

Howsomevers; because of THE LAW, you can "trick" 6-volt ignition coils (or other electrical stuff like lightbulbs) to run on 12-volts by using a 12-to-6 volt converting resistor. (just as you are tricking the squarecan ignition coil to run on 6-volts by using the "infamous ballast resistor") Works everytime.

ONLY the 6-volt squarecan frontmount ignition coil always uses a resistor. (whether 6-or-12 volt battery, and the type and value of resistor CHANGES depending upon the battery, its THE LAW) The 6-volt roundcan sidemount ignition NEVER uses a resistor on 6-volts. Its THE LAW. Understand?..... .respectfully, Dell, the NON-lawyer

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Phil (NJ,Az,SasK)

02-19-2007 16:43:19




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 Re: 12v coil ? on 6 volt ? in reply to uh . . . Dell (WA), 02-18-2007 08:26:31  
[quote]WHY? because every electrical component has to be designed specifically for its own operating voltage. Resistors REDUCE VOLTS and can NOT INCREASE volts. EVER!!! Its the LAW!!! [/quote]

Dell, You need to re-think that statement.
Its resistors that reduce "current" in a circuit, and added resistors redistribute voltage in the circuit. The largest resistor, in a circuit, will have the largest voltage drop, so I don't understand your point.

JMHO

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