Sorry..another O/T (case of the stupids)

BrianRBM

Member
I know there are some smart guys here so please help and explain answer. Joe can plow a field in 4 hrs. Frank plows the same field in 6 hrs. How long would it take if they both plowed together to plow the field? The answer is 2 hrs and 24 min but I can't for the life of me see how its calculated. Thanks. Oh, there is no tricks with equipment,etc. ....just a straight time thing.
 
Joe's rate is 1 field per 4 hours = 1/4. Frank's rate is 1 field per 6 hours. Let t= time it takes for both of them to plow 2 field.
1/4t + 1/6t = 1 field.
6/24t + 4/24t = 1
10/24t = 1
t = 2.4 hours = 2 hours 24 mins.
 
Alternatively (really the same just rearranging it):

In 6 hours Frank would plow 1 field and Joe would plow 1.5 fields,
so their rate is 6 hours per 2.5 fields,
or 6 hrs / 2.5 fields = 2.4 hrs/field = 2 hrs 24 minutes/field
 
Yeah but if joe plowed half the field in 2 hours and frank plowed the other half in 3 hours then joe would have helpede joe after finishing his half so frank would have got done another 1/2 hour sooner but joe would have still plowed more than frank so frank would not have 30 minutes plowing left so after 20 minutes after the 2 hour mark they still would be not quite done so---

Why the heck don't frank get the same tractor and plow that joe has and they would have finished in 2 hours flat?

Easier to figure also if Frank would just get a bigger plow and tractor.

Gary
 
I'd think it'd take longer, because they'd have to stop after 5 rounds to tell each other how to plow properly...

Donovan from Wisconsin
 
I know I know!!!

Lets say the field was 24 acres soooo

Joe plows 6 acres a hour and Frank plows 4 acres a hour.

That makes 10 acres a hour between the 2 plows.

Soooo if they plow 24 acres at 10 acres an hour that means it will take 2.4 hours or 2 hours and 24 minutes.

Still would more fair if Frank would get that bigger plow.

Gary
 
Joe is hard worker and gets the job done quickly. Frank works for the Gov't. and has to ponder the job for an extra 2 hours while 3 other Gov't. workers lean on shovels watching him. Dave
 
If Joe left Topeka on his tractor going East at 16.9 mph and Frank left Topeka on his tractor going West at 4.9 mph (it was a N series Dorf), they probably would never meet.
 
I actually came up with the correct answer too, but it was more trial and error. Your solution is the right one. Thanks.
 
I think it depends on which guy has to plow the part with the soft spot- you know, over in that swale on the back side. . . Where Grandpa buried the Oil Pull that time. . .
 
It's the old work problem from math class. If A can do the job in 4 hrs, he does 1/4 of the job per hr. B can do 1/6 of job per hr. If they both work, let's say x hrs, then 1/4x+1/6x=1 (1 being the 1 whole job) Solve the equation, find x to be 2.4 More fun than football, only half the knee injuries.
 

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