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Does anyone know the math?

B

Blackstack

Member
How much of a percentage of the engine torque does a mechanical style TA clutch see? I've got my 460 tore apart and am debating on beefing up the TA clutch. It's just a loader tractor but who knows, in 2-3 years it may have a 301 or a 560 engine put in if the original one goes south. 7" organic TA clutch disk looks good. Pressure plate looks good. I had to take it apart to put a TA throw out bearing in so now's the time to do something if I'm going to. What do you guys think? I thought about putting heavier springs in or adding 3 more springs to the existing 3 small holes and putting it back together with the existing TA clutch disk. Don't feel like shelling out $70 for a new one when mine looks to be about 70-80 percent.
 
The hundred, 50, and 60 series used the same TA. My friend has a 560 bored out to around 360 inches, he only pulls with it but it's holding up. Letting them over-run is what takes them out.
 
That"s what I couldn"t figure out. If the TA clutch takes the 2/3rds and the one way takes 1/3rds or if it were actually the inverse of that.
 
(quoted from post at 14:48:34 11/29/10) Abou 2/3. The gear ratio is ~33% so the split is 1/3-2/3 with the one way taking the remainder Jim
Click to expand...

Very close, except the one way clutch is not involved when the TA clutch is engaged.

Power is applied to the sun shaft. With the TA clutch released the carrier is held by the one way clutch and power is transmitted from the sun shaft, through the pinion gears, and out through the output shaft. Assuming a 2/3 gear ratio, does the one way clutch have to hold 1/3 or 2/3 of the torque?

The TA clutch only has to hold the sun shaft stationary with relation to the carrier. So does the clutch carry 1/3 or 2/3 of the load?

To add more complications, there are two different gear ratios on the planetary gears.

Whatever the real answer is, the torque that the TA clutch has to control is much less than engine torque.
 
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