Need an opinion

Anonymous-0 · Oct 5, 2009

I'd like to solve two problems at once, but not
sure I'm looking at this the right way. I'd like
to build a log splitter and run it off my F560's
spare hydraulics. I'd also like to speed up my
loader which is something the previous owner
cobbled together from a loader from another
tractor which was shortened to fit. Part of what he did was to install two 4" diameter cylinders
on the lift arms. With the 12 gpm flow out of the
560 pump this makes for slow lifting. I thought
about replacing the two 4" dia. cylinders with
a couple of 2" dia. of the same length. The
smaller cylinders should fill roughly twice as fast as the larger ones and speed up the lift
action. Yes, I'll have less lift capacity, but
I think it will handle most of what I would ever
want to do with my 6' bucket. The 4" cylinders would work great for the splitter with one left for a spare. Any opinions appreciated.

Doug - Iowa · Oct 5, 2009

You're on the right track but your math is a bit off. Remember you are dealing with volume so you need to calculate the area of the piston and then compare the volume. For instance, your 4" dia cylinder has a piston area of 12.57 sq.in. so it will reguire 12.57 cubic inches volume per inch of stroke. A 2" dia has 3.14 cubic inches volume per inch of stroke. To halve the volume you probably would be better with a 3" cylinder giving you 7.07 cu in per inch per cylinder.

This site makes the math easier...

http://www.surpluscenter.com/Hydraulic.htm

IH fan · Oct 5, 2009

(quoted from post at 13:08:40 10/05/09) Part of what he did was to install two 4" diameter cylinders
on the lift arms. With the 12 gpm flow out of the
560 pump this makes for slow lifting. I thought
about replacing the two 4" dia. cylinders with
a couple of 2" dia. of the same length. The
smaller cylinders should fill roughly twice as fast as the larger ones and speed up the lift
action.

Try about 4 times as fast... You have 4 times the area if you remember your formula for figuring the area of a circle... you will have approx. 12.5664 square inches of area on a 4" cylinder and 3.1416 on a 2" diameter cylinder. the lifting force will also be 1/4 of what it was. I would opt for something in between, to still have both decent lifting power and speed if you size it right. 3" cylinder will be 7.0686, or a little more than 1/2 the area you now have, so lift and speed will change accordingly.
added:
I see us old Iowa boys were thinking along tha same lines.

Haas · Oct 5, 2009

Like the others said, it will go 4 times as fast, but it will also have 1/4 the capacity that it has with the 4 inch cylinder. Maybe you should go with a 3 inch cylinder which will reduce the capacity about 44 percent and speed it up by about 78 percent. Not quite double the speed and not quite half the previous capacity.

armand tatro · Oct 5, 2009

Under no circumstances reduce the size of your boom cylinders!!!! Sooner or later you will bend smaller cylinders since you have a 6 ft. bucket. A better option would be to get a new 16 gpm. pump. This will make the log splitter and loader both work faster. I upgraded my 560D to the 16gpm. pump when my old one wore out and have had good luck with it. Also make sure the hyd. oil is not bypassing in either your valves or the cylinders. I have bent a small-diameter cylinder and by the time you pay to fix the cyl. you will have at least 1/2 the price of the 16gpm. pump in the cyl. repairs and possibly do damage to the loader frame. Armand

Need an opinion

Anonymous-0

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Doug - Iowa

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IH fan

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Haas

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armand tatro

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